Ch 7.2 Applications of the Normal Distribution

February 3, 2018 | Author: Anonymous | Category: Math, Statistics And Probability, Normal Distribution
Share Embed Donate


Short Description

Download Ch 7.2 Applications of the Normal Distribution...

Description

Modular 12 Ch 7.2 Part II to 7.3

Ch 7.2 Part II Applications of the Normal Distribution Objective B : Finding the Z-score for a given probability Objective C : Probability under a Normal Distribution Objective D : Finding the Value of a Normal Random Variable

Ch 7.3 Assessing Normality Ch 7.4 The Normal Approximation to the Binomial Probability Distribution (Skip) Objective A : Continuity Correction

Objective B : A Normal Approximation to the Binomial

Ch 7.2 Applications of the Normal Distribution Objective B : Finding the Z-score for a given probability

Area  0 . 5

Area  0 . 5

Area  0 . 5

Example 1 : Find the Z-score such that the area under the standard normal curve to its left is 0.0418.  1 . 73 )  0.0418 P ( Z  _____

From Table V 0 . 03

0 . 0418  1 .7 Z ?

0

0 . 0418

Example 2 : Find the Z-score such that the area under the standard normal curve to its right is 0.18. From Table V 0 . 92 P ( Z  ______ )  0.18 0 . 02

1  0 . 18  0 . 82

0 . 18 0 .9

0 . 8186

0 . 8212

(Closer to 0.82)

Z ?

Example 3 : Find the Z-score such that separates the middle 70%.  1 . 04  Z  _____ 1 . 04 )  0.70 P ( _____

70 % Z ?

From Table V 0 . 04

Z ?

15 %

15 %

or 0 . 15

or 0 . 15

Z   1 . 04

 1 .0

Z  1 . 04 ( Due to symmetry )

0 . 1515

0 .1 4 9 2

(Closer to 0.15)

Ch 7.2 Part II Applications of the Normal Distribution Objective B : Finding the Z-score for a given probability

Objective C : Probability under a Normal Distribution Objective D : Finding the Value of a Normal Random Variable

Ch 7.3 Assessing Normality Ch 7.4 The Normal Approximation to the Binomial Probability Distribution Objective A : Continuity Correction

Objective B : A Normal Approximation to the Binomial

Ch 7.2 Applications of the Normal Distribution Objective C : Probability under a Normal Distribution Step 1 : Draw a normal curve and shade the desired area.

Step 2 : Convert the values of

X

to

Z

– scores using

Z 

X 



.

Step 3 : Use Table V to find the area to the left of each Z – score found in Step 2. Step 4 : Adjust the area from Step 3 to answer the question if necessary.

Example 1 : Assume that the random variable X is normally distributed with mean   50 and a standard deviation   7 . (Note: This is not a standard normal curve because   0 and   1 .)  (a) P ( X  58 ) Z   

X 

 58  50

50

7



8

 1 . 14

58

X

0 .8 7 2 9

7

P ( Z  1 . 14 )

From Table V  0 .8 7 2 9

0 1 . 14

Z

(b) P ( 45  X  63 ) X  63

X  45 Z  

X 



X 

Z 

45  50

0 . 2389

63  50



7

5

7 Z   0 . 71

0 . 9686



7 





13

7 Z  1 . 86

P (  0 . 71  Z  1 . 86 )

From Table V  0 . 71  0 . 2389 1 . 86  0 . 9686  0 . 9686  0 . 2389  0 . 7297 ( the whole blue area )

 0 . 71

0

1 . 86

Z

Example 2 : GE manufactures a decorative Crystal Clear 60-watt light bulb that it advertises will last 1,500 hours. Suppose that the lifetimes of the light bulbs are approximately normal distributed, with a mean of 1,550 hours and a standard deviation of 57 hours, what proportion of the light bulbs will last more than 1650 hours? 

P ( X  1650 ) X  1650 ,   1550 ,   57 Z 



0 . 0401

X 



0

1650  1550 57



0 . 9599

100 57

Z  1 . 75

P ( Z  1 . 75 )

From Table V 1 . 75  0 . 9599

 1  0 . 9599  0 . 0401

1 . 75

Z

Ch 7.2 Part II Applications of the Normal Distribution Objective B : Finding the Z-score for a given probability Objective C : Probability under a Normal Distribution Objective D : Finding the Value of a Normal Random Variable Objective E : Applications

Ch 7.3 Assessing Normality Ch 7.4 The Normal Approximation to the Binomial Probability Distribution Objective A : Continuity Correction

Objective B : A Normal Approximation to the Binomial

Ch 7.2 Applications of the Normal Distribution Objective D : Finding the Value of a Normal Random Variable Step 1 : Draw a normal curve and shade the desired area. Step 2 : Find the corresponding area to the left of the cutoff score if necessary. Step 3 : Use Table V to find the Z – score that corresponds to the area to the left of the cutoff score. Step 4 : Obtain x from

Z

by the formula

Z 

X 



or

x    z

.

Ch 7.2 Applications of the Normal Distribution Objective D : Find the Value of a Normal Distribution Example 1 : The reading speed of 6th grade students is approximately normal (bell-shaped) with a mean speed of 125 words per minute and a standard deviation of 24 words per minute. (a) What is the reading speed of a 6th grader whose reading speed is at the 90% percentile?   125 ,   24 , Z  1 . 28 90 % or 0 . 9

Solve for X Z  1 . 28

From Table V 0 . 08

Z  1 . 28 

X 

 X  125 24

1 . 28 ( 24 )  X  125 1 .2

0 . 8997

(Closer to 0.9)

0 . 9015

X  1 . 28 ( 24 )  125 X  155 . 72

words per minute

(b) Determine the reading rates of the middle 95% percentile.   125 ,   24 , solve for X

95 % or 0 . 95

Z   1.96

Z ?

Z ?

2 .5 %

2 .5 %

or 0 . 025

or 0 . 025

Z   1.96

Z  1.96 due to sym m etry

Z 

 1.96 

X 

 X  125 24

 1.96 (24)  X  125

From Table V 0 .0 6

X   1.96 (24)  125 X  7 7 .9 6

 1 .9

0 . 025

words per minute

Z  1 .9 6 Z 

1.96 

X 

 X  125 24

1.96 (24)  X  125

X  1.96 (24)  125 X  1 7 2 .0 4

words per minute

Ch 7.2 Part II Applications of the Normal Distribution Objective B : Finding the Z-score for a given probability Objective C : Probability under a Normal Distribution Objective D : Finding the Value of a Normal Random Variable

Ch 7.3 Assessing Normality Ch 7.4 The Normal Approximation to the Binomial Probability Distribution Objective A : Continuity Correction

Objective B : A Normal Approximation to the Binomial

Ch 7.3 Assessing Normality Ch 7.3 Normality Plot Recall: A set of raw data is given, how would we know the data has a normal distribution? Use histogram or stem leaf plot. Histogram is designed for a large set of data.

For a very small set of data it is not feasible to use histogram to determine whether the data has a bell-shaped curve or not. We will use the normal probability plot to determine whether the data were obtained from a normal distribution or not. If the data were obtained from a normal distribution, the data distribution shape is guaranteed to be approximately bell-shaped for n is less than 30.

Perfect normal curve. The curve is aligned with the dots.

Almost a normal curve. The dots are within the boundaries.

Not a normal curve. Data is outside the boundaries.

Example 1: Determine whether the normal probability plot indicates that the sample data could have come from a population that is normally distributed.

(a)

Not a normal curve. The sample data do not come from a normally distributed population.

(b)

A normal curve. The sample data comes from a normally distribute population.

View more...

Comments

Copyright � 2017 NANOPDF Inc.
SUPPORT NANOPDF