CSCA67 Week 1 Lecture Notes - University of Toronto Scarborough

Welcome to CSCA67 Discrete Mathematics for Computer Scientists Anna Bretscher and Richard Pancer AA112

Bretscher

Fridays 10:10-12pm

SY110

Pancer

Fridays 13:10-14pm

Evaluation Assignments – 4 each worth 10%

– Late assignments will be accepted up to 24 hrs late with a penalty of 25% – You are encouraged to discuss the problems with other students however, the actual write up must be an individual effort – You must be able to reproduce any solution that you submit. The penalty for cheating ranges from a zero on the assignment to suspension from the university

Evaluation Term Test – Week 7 or 8 worth 20%

Final Exam – Worth 40%

Resources Course Slides Posted each week. Print them and bring to class. Website http://www.utsc.utoronto.ca/bretscher/a67/f14 Check the announcements daily. Textbook Stein, Drysdale and Bogart, Discrete Mathematics for Computer Scientists Office Hours Tutorials 4

Course Expectations Expectations of the lecturer • Give clear, organized lectures • Assign fair, challenging assignments that ensure that you, the student, understand the material

• Be available for help in office hours • Help every student achieve their goals in the course (this requires your help!)

Course Expectations Expectations of the student • Attend lectures and participate

• Bring course notes to class • Review lecture notes after each class, not just before the exam

• Complete homework fully, neatly and independently • Have respect for your classmates and lecturers

Discrete Mathematics Who needs it? Anyone in computer science or a mathematical science

Why? In CS we need to be able to

• speak precisely without ambiguity • analyze problems and • formulate solutions

• apply the concepts associated with probability, graph theory and counting theory.

CS is Applied Mathematics! Specifically, we will work on: – Thinking abstractly – Expressing ourselves precisely – Arguing logically – i.e., inferring conclusions that necessarily result from assumptions – Writing rigorous solutions – Learning how mathematics and computer science work together

Where Does Mathematics Appear in Computer Science? Computer Graphics

Multivariable calculus, physicsbased modelling

Digital Signal Processing

Multivariable calculus, (eg., speech understanding)

Numerical Analysis

Multivariable calculus, linear algebra

Cryptography

Number theory

Networking Algorithms

Graph theory, statistics, combinatorics, probability, set theory

Where Does Mathematics Appear in Computer Science? Databases

Set theory, logic

Artificial Intelligence

Set theory, logic

Programming Languages

Set theory, logic

Formal Methods

Set theory, logic for the specification and verification of hardware and software; (e.g., nuclear, aviation – NASA!)

Course Outline Counting 3 weeks Probability 2 weeks Proofs 3 weeks Graph Theory 3 weeks

How Do I Become Good At This Stuff?

BY FAILING! WHAT ??? Every time you fail at solving a problem, you learn something. You take a step closer to the solution.

Let’s Talk About Counting Counting shows up everywhere… Even when ordering pizza.

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Counting Pizza Toppings Q. Are there really 1,048,576 possibilities? A. No! The commercial got it wrong. Let’s count it ourselves.

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Counting Pizza Toppings* The commercial’s deal was: • 2 pizzas • up to 5 toppings on each • 11 toppings to choose from • all for $7.98 (back in 1997). The commercial’s math kid claimed there are 1,048,576 possibilities. *http://mindyourdecisions.com/blog/2011/04/27/math-problem-pizza-topping-combinations 15

Let’s Do The Calculation Q. How many ways can we order a pizza with 0 toppings? A. 1

Q. How many ways can we order a pizza with 1 topping? A. 11 16

Let’s Do The Calculation Q. How many ways can we order a pizza with 2 toppings? A. – 11 choices for the first topping (assume no “double” toppings) – 10 choices for the second would give 10 x 11 = 110. – Order does not matter, so 110/2 = 55.

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Let’s Do The Calculation Q. How many ways can we order a pizza with 3 toppings? A. 11 x 10 x 9 ways to select the toppings (assume no “double” toppings) Does the order the toppings are picked matter? How many times have we over counted? 18

Let’s Do The Calculation Q. How many times have we over counted? Let our toppings be called x, y and z. Equivalent pizzas: xyz xzy yxz yzx zxy zyx Can think of this as 3 choices for the first topping, 2 for the second, 1 choice for the last topping. 3x2x1=6 Total: (11 x 10 x 9) / 6 19

Let’s Do The Calculation Q. How many ways can we order a pizza with 4 toppings? A. 11 x 10 x 9 x 8 ways to select the toppings (assume no “double” toppings) How many times have we over counted? 4 x 3 x 2 x 1 = 4! = 24 So (11 x 10 x 9 x 8) / 4! 20

Let’s Do The Calculation Q. How many ways can we order a pizza with 5 toppings? A. 11 x 10 x 9 x 8 x 7 ways to select the toppings (assume no “double” toppings) How many times have we over counted? 5 x 4 x 3 x 2 x 1 = 5! = 120 So (11 x 10 x 9 x 8 x 7) / 5! 21

Let’s Do The Calculation So the total number of ways to order a pizza with up to 5 toppings choosing from 11 toppings is: 1 + 11 + (11 x 10)/2 + (11 x 10 x 9)/3! + (11 x 10 x 9 x 8)/4! + (11 x 10 x 9 x 8 x 7)/5! = 1 + 11 + 55 + 165 + 330 + 462 = 1024

Q. How did they get 1,048,576 in the commercial?

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Let’s Do The Calculation Q. How did they get 1,048,576 in the commercial? A. Two pizzas. So for each of the 1024 choices for the first pizza, there are 1024 choices for the second pizza. 1024 x 1024 = 1, 048, 576 Q. Is 1,048,576 the correct answer? A. No. Why not? 23

Let’s Do The Calculation Q. Why isn’t 1,048,576 the correct answer? A. We have over counted something. The order of any two pizzas doesn’t matter (Pizzas A, B are the same as B, A). Q. How do we correct this? A. Divide by 2: 1,048,576 ÷ 2 = 524, 288.

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Let’s Do The Calculation Q. Is 524,288 the correct answer? A. No. We have under counted something. There are not two orderings when we order two identical pizzas (A, A). But we divided by 2 before. Q. How do we correct this? 25

Let’s Do The Calculation Q. How do we correct this? A. Add back half of the number of identical pizzas. Q. How many pairs of identical pizzas are there? A. 1024. Final answer: 524,288 + 1024÷2 = 524,288 + 512 = 524,800 26